Answer:
Consider the parent logarithm function f(x) = log(x)
Now,
Let us make transformations in the function f(x) to get the function g(x)
•On streching the graph of f(x) = log(x) , vertically by a factor of 3, the graph of y = 3log(x) is obtained.
•Now, shrinking the graph of y = 3log(x) horizontally by a fctor of 2 to get the grpah of y = 3log(x/2) i.e the graph of g(x)
Hence, the function g(x) after the parent function f(x) = log(x) undergoes a vertical stretch by a factor of 3, and a horizontal shrink by a factor of 2 is
g(x) = 3 log(x/2) (Option-B).
He still has 75% of his income left because 1500/375=4 so he spent 1/4 of his check and has 3/4 left.
A number squared would be x squared (x^2)
The product of x squared and ten is 10x^2
Then subtract nine
10x^2 - 9
Let X be the number of boys in n selected births. Let p be the probability of getting baby boy on selected birth.
Here n=10. Also the male and female births are equally likely it means chance of baby boy or girl is 1/2
P(Boy) = P(girl) =0.5
p =0.5
From given information we have n =10 fixed number of trials, p is probability of success which is constant for each trial . And each trial is independent of each other.
So X follows Binomial distribution with n=10 and p=0.5
The probability function of Binomial distribution for k number of success, x=k is given as
P(X=k) = ![(10Ck) 0.5^{k} (1-0.5)^{10-k}](https://tex.z-dn.net/?f=%20%2810Ck%29%200.5%5E%7Bk%7D%20%281-0.5%29%5E%7B10-k%7D%20%20)
We have to find probability of getting 8 boys in n=10 births
P(X=8) = ![(10C8) 0.5^{8} (1-0.5)^{10-8}](https://tex.z-dn.net/?f=%20%2810C8%29%200.5%5E%7B8%7D%20%281-0.5%29%5E%7B10-8%7D%20%20)
= 45 * 0.0039 * 0.25
P(X = 8) = 0.0438
The probability of getting exactly 8 boys in selected 10 births is 0.044
Answer:
12.33
Step-by-step explanation:]
450-80=370/30=12.33