Answer:
Step-by-step explanation:
Suppose the dimensions of the playground are x and y.
The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore, y= 780/2-3/2x. Now, the total area (A )to be fenced is
A=x*y= x*(390-3/2x)=-3/2 x^2+390x
Calculating the derivative of A and setting it equals to 0 to find the maximum
A'= -3x+390=0
This yields x=130.
Therefore y=780/2-3/2*130=195
Thus, the maximum area is 130*195=25,350ft^2
Maybe the money you owe someone
Area of a semicircle is 1/2* πr^2
Area of a square is s^2
Square’s area: 4mm^2
The radius is 3mm
Plug into the equation
1/2* π(3^2)
1/2* π(9)
We can use 3.14 as an estimate of pi
1/2*28.26
14.13mm^2
Now just add them both
Total area 18.13mm^2
Answer:
20.625 dollars or about 20.63 dollars
Step-by-step explanation:
33/8 = 4.125
4.125 times 5 = 20.625
Answer:
(0.4958, 0.7422)
Step-by-step explanation:
Let p be the true proportion of water specimens that contain detectable levels of lead. The point estimate for p is 
. The estimated standard deviation is given by 
. Because we have a large sample, the 90% confidence interval for p is given by 
where 
is the value that satisfies that above this and under the standard normal density there is an area of 0.05. So, the confidence interval is 
, i.e., (0.4958, 0.7422).
