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OlgaM077 [116]
2 years ago
7

An 8-foot piece of pipe is cut into 1/3 foot sections. How many sections of pipe are there?

Mathematics
2 answers:
Sunny_sXe [5.5K]2 years ago
6 0
If you cut an 8 foot pipe into 1/3 foot sections that would be B. 24 sections of 4" pipe
Paul [167]2 years ago
5 0
B) I hope this helped:)
You might be interested in
The diameter of a circle is 16 meters what is the area
KengaRu [80]

Answer:

201.1 meters squared

Step-by-step explanation:

A= pi*r squared

Diameter= 16, to find the radius we must divide by 2

16/2=8

Radius= 8

A= pi* (8)^2

A= 201.06

The area of the circle is 201.1 meters squared.

3 0
2 years ago
What is the sequence for 6,12,18,24
scoundrel [369]

Answer:

an =6n

Step-by-step explanation:

6,     12,      18,     24

Take the 2nd number minus the first number,  3rd minus the second, etc

12-6  =6

18-12 = 6

24-18 =6

The common difference is 6

The formula for an arithmetic sequence is

an =a1+d(n-1)

 where a1 is the first term

  d is the common difference

 n is the term number

an = 6+6(n-1)

 Distributing

     = 6+6n-6

     = 6n

7 0
3 years ago
Which of the following statements is TRUE about the midline of a trapezoid?
Y_Kistochka [10]

Answer:

C will be the rightful answer

3 0
2 years ago
Find the area of the figure​
Alex17521 [72]

Answer:

To find area of parallelogram, multiply base and height

Step-by-step explanation:

Base is 6, height is 4

6 x 4 =  x

x = 24

4 0
3 years ago
If f(x)=sinx 2x 1 and g is the inverse function of f
Bingel [31]

The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.

<h3>What is an inverse function?</h3>

A function that may convert into another function is known as an inverse function or anti-function.

If the function is f(x) = sinx + 2x + 1.

Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be

\rm g'(a) = \dfrac{1}{f'(g(a))}

The derivative of f(x) will be

f'(x) = cos x + 2

Then the given value of a will be

a = 1

g(x) = f⁻¹(x)

put x = 0, then we have

f(0) = sin 0 + 2(0) + 1

f(0) = 1

Put x = 1, in the function f⁻¹(x). Then we have

f⁻¹(1) = 0

and

g(1) = 0

Then put a = 1, then we have

\rm g'(a) = \dfrac{1}{f'(g(a))}\\\\g'(1) = \dfrac{1}{f'(g(1))}\\\\g'(1) = \dfrac{1}{f'(0)}\\\\g'(1) = \dfrac{1}{\cos 0 + 2}\\\\g'(1) = \dfrac{1}{1+2}= \dfrac{1}{3}

More about the inverse function link is given below.

brainly.com/question/2541698

#SPJ4

8 0
2 years ago
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