The average score for the entire year is 88.44444, so by rounding down the answer is 88%
An expression that is equivalent to 2.3 x 2.3 x 2.3 x 2.3 x 2.3 is 2.3^
Answer:
Step-by-step explanation:
⅓x + 7 = -2
isolate the x term by subtracting 7 from both sides
⅓x = -9
Multiply both sides by 3
x = -27
The percentage of young adults send between 128 and 158 text messages per day is; 34%
<h3>How to find the percentage from z-score?</h3>
The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.
We are given;
Sample mean; x' = 158
Population mean; μ = 128
standard deviation; σ = 30
We want to find the area under the curve from x = 248 to x = 158.
where x is the number of text messages sent per day.
To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;
z = (x - μ)/σ
z = (158 - 128)/30
z = 30/30
z = 1
This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.
From online p-value from z-score calculator, we have;
P-value = 0.34134 = 34%
Approximately 34% of the the population sends between 128 and 158 text messages per day.
Read more about p-value from z-score at; brainly.com/question/25638875
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The distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.
<h3>What is the distance between the points (23,-33) and (4,9)?</h3>
The distance between two points on a graph can be determined using the equation;
D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]
Given that;
- x₁ = 23
- x₂ = 4
- y₁ = -33
- y₂ = 9
We substitute our values into the equation above.
D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]
D = √[ ( 4 - 23 )² + ( 9 - (-33) )² ]
D = √[ ( -19 )² + ( 42 )² ]
D = √[ 361 + 1764 ]
D = √[ 2125 ]
D = 46.10
Therefore, the distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.
Learn more about distance formula here: brainly.com/question/7592016
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