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Scilla [17]
2 years ago
10

Again another Pythagorean Theorem i need help on, please and thank you

Mathematics
1 answer:
vodka [1.7K]2 years ago
6 0

     You commented that part of the instruction included "If the theorem cannot be applied, explain the reason."

     The theorem cannot be applied. Since this is not a right triangle, we cannot solve using the Pythagorean Theorem unless we are given a height. If we have the height of this triangle, then we can break it into two different right triangles and solve.

What is a right triangle? A right triangle is a triangle that has an angle measurement of 90 degrees.

       In summary, this is an isosceles triangle and the Pythagorean Theorem only applies to right triangles.

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Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =
dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27­°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

8 0
3 years ago
the figure below shows two half-circles at the ends of a rectangle with the dimensions shown. which is the closet to the area of
Pani-rosa [81]
You get 92.56 <span>You add the area of the rectangle to the area of a circle

</span>
8 0
3 years ago
Find the length of side s to the nearest tenth.
bulgar [2K]

Answer:

  10.3

Step-by-step explanation:

The triangle can be solved from one side and two angles by using the angle sum theorem to find the third angle, then using the Law of Sines to find the remaining sides.

The angle at T is ...

  180° - 119° -36° = 25°

The law of sines tells us side s will be ...

  s/sin(S) = t/sin(T)

  s = sin(119°)×5/sin(25°) . . . . multiply by sin(S)

  s ≈ 10.34763

  s ≈ 10.3

__

<em>Additional comment</em>

  u/sinU = t/sin(T)

  u = sin(36°)×5/sin(25°) ≈ 6.95409

5 0
2 years ago
Line segment ON is perpendicular to line segment ML. Line segment OM = 13 units in length, line segment PN = 8 units in length.
Alex_Xolod [135]

Answer:

24

Step-by-step explanation:

Line segment ON is perpendicular to line segment ML. Line segment OM = 13 units in length, line segment PN = 8 units in length.

Circle O is shown. Line segments M O, N O, and L O are radii. Lines are drawn to connects points M and N and points N and L to form chords. A line is drawn from point M to point L and intersects line O N at point P. The length of O M is 13 and the length of P N is 8. Angle O P L is a right angle.

3 0
3 years ago
Read 2 more answers
a diver begins a sea level and dives down 200 feet. he ascends at a steady rate of 12 and 1 thirds feet per minute for 4.5 minut
Komok [63]

12 1/3 x 4.5 = 55 1/2 feet

-200 + 55 1/2 = -144 1/2

 the diver is at  -144 1/2 feet

4 0
3 years ago
Read 2 more answers
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