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Eddi Din [679]
3 years ago
15

Osceres

Mathematics
1 answer:
Igoryamba3 years ago
6 0

Answer:

∠B = 12°

∠C = 180 - 48° = 132° ( straight line angle = 180)

Sum of angles of a triangle = 180°

180 =  ∠A + ∠B + ∠C

180 = ∠A + 12 + 132

180 - 144 = ∠A

∠A =  36°

option B

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George and Cameron went on a bycicle trip. They took a bus to their starting point, and then biked the rest. They traveled 325 k
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Let the distance travelled by bus be x and the distance travelled be bike be (x+75)

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3. Kurt's car gets 23 miles to a gallon of gasoline. He filled up his car's gas tank with g gallons. Write an expression that sh
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The expression D=23g shows the distance that Kurt can drive on a tank of gasoline.

Step-by-step explanation:

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The probability that a person in the United States has type B​+ blood is 10%. Four un-related people in the United States are se
marysya [2.9K]

Answer:

a. 0.0001

b. 0.6561

c. 0.3439

d. B. The event in part​ (a) is unusual because its probability is less than or equal to 0.05.

Step-by-step explanation:

a. # We are given that the probability that a person in the United States has Type B+ blood = 0.10. Also we are told that four unrelated people in the United States are selected at random.

#We have to find here the probability that all four have type B+ blood.

Since the events are independent, we have :

Probability that all four have B+ blood  = 0.10 x 0.10x 0.10x0.10

                                                                                       = 0.0001

Therefore, the probability that all four have type B+ blood is 0.0001

b. We have to find the probability that none have B+ blood. Using the complementary law of probability we have:

Probability that blood type is not B+ = 1 - 0.10= 0.90                                                                        

Therefore, the probability that none have B+ blood

= 0.90 x 0.90 x 0.90x0.90=0.6561

Therefore, the probability that none have B+ blood is 0.6561

c. We have to find the probability that at least one of the four have B+ blood.

#The probability that at least one of the four have B+ blood = 1 -  Probability that none have B+ blood type

=1-0.6561=0.3439

Therefore,the probability that at least one of the four has type B+ blood is 0.3439

d. An event is considered unusual if the probability of the event is small or less than 0.05 . We note that event a is the only small probabilty and is less than 0.05.

-a is thus considered unusual(the rest are all usual events)

                                                                                                                 

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2 years ago
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