1.6 6x4=24
x4
____
6. 4
2
don't know if u get it but here u go
-20.01
-20.02
-20.03
and so on
all the way to 20.99
We notice that:
9-6 = 3
12-9 = 3 , Then we can conclude that this is an arithmetic progression with:
1st term a₁ = 6 and with common difference d = 3
So the first term is 6 and the last term is 93.
the formula of the sum in a A.P is :
S = (a + last term).n/2, n being the rank of the last term. So to be
able to find S, we have to calculate the value of n
We know that the last value of a A.P is :
last value = a₁ + (n-1)d
93 = 6 +(n-1)(3) → 93 = 6 + 3n -3 → n = 90/3 → n = 30 (rank 30th)
Now we can find the sum:
S = (a₁ + last term)n/2
S = (6+93)30/2
S = (99).15 = 1,485
Answer:
Step-by-step explanation:
x + 2y = 14 ...............(1)
6x + 3y = 21 ..............(2)
Solve for x in equation 1
When x + 2y = 14
Therefore x = 14 - 2y ...................(3)
Now put equation 3 in equation 2 and solve
6x + 3y = 21 .............(2)
6(14 - 2y) + 3y = 21
Open the bracket and resolve
84 - 12y + 3y = 21
-9y + 84 =21
Now collect the like terms
-9y + 84 = 21
-9y = 21 - 84
-9y = -63
Divide through by -9 to get y
y = -63/-9
y = 7
Substitute for y in equation( 3 )to x
x= 14 - 2y............(3)
So, x = 14 - 2(7)
x = 14 - 14
x = 0.
Therefore x = 0 and y = 7
Check: From equation (1)
x + 2y = 14
Now, put x = 0 and y = -2
Therefore, 0 +2(7) =14
0 +14 = 14
Step-by-step explanation:
