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3 years ago

Help me please... Anyone out there... I need help.....

Mathematics

1 answer:

dsp733 years ago

8 0

I think its C..either C or D delete all the others from the thing.

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PLEASE HELP SOON!! AS POSSIBLE

NemiM [27]

I believe the anwser is c.

8 0

3 years ago

I don't get this... someone explain this plum thing please...... Before a plum is dried to become a prune, it is 92% water. A pr

taurus [48]

Answer:

21.74 But if it tells you to round I would round to 21 lbs

Step-by-step explanation:

its basically just a ratio of 92 to 20

92/20=4.6

92-20=72% the amount that is lost

so given that the plum is 100 lbs we know that 72% is depleted

(72/92 = .78)X100= 78 lbs depleted

Lastly 100-78 =22 for the remaining weight of the prunes.

4 0

3 years ago

2(4x − 3) − 8 = 4 + 2x<br> steps

asambeis [7]

Answer:

X=3

Step-by-step explanation:

2(4x-3)-t=4+2x

multiply parentheses by 2

8x-6-8=4+2x

Calculate

8x-14=4+2x

Move terms

8x-2x=4+14

Calculate the sum after collecting like terms

6x=18

Divide both sides by 6

x=3

6 0

3 years ago

Read 2 more answers

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

3 years ago

The mean of 4 numbers is 32. If three of the numbers are 15, 21, and 75, what is the value of the fourth number?

IgorLugansk [536]

If the mean is 32 and there is 4 numbers
then the numbers add to 32x4 which is 128
128-15-21-75=17
fourth number is 17

4 0

2 years ago

Read 2 more answers