5 odd numbers and 5 even numbers
since they can be repeated
5*5*5=first 3 digits
5*5*5=last 3 digits
in all
5*5*5*5*5*5=15625 ways
Answer:
AB = 2
Step-by-step explanation:
Using the secant- secant theorem, that is
PA × PB = PD × PC , substitute values
10(10 + AB) = 8(8 + 7)
100 + 10AB = 8 × 15 = 120 ( subtract 100 from both sides )
10AB = 20 ( divide both sides by 10 )
AB = 2
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>att</em><em>ached</em><em> </em><em>picture</em>
<em>hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em>
A = 1
4/17=2/8.5
...................
Answer:
D. -12s squared + 11st - 2t squared
Step-by-step explanation:
FOIL:
-3s(4s) - 3s(-t) + 2t(4s) + 2t(-t)
- 12s² + 3st + 8st - 2t²
Simplify.
- 12s² + 11st - 2t²
