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RideAnS [48]
3 years ago
14

If four items are chosen at random without replacement from seven items, in how many ways can the four items be arranged, treati

ng each arrangement as a different event (i.e., if order is important)?
Mathematics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

840 ways.

Step-by-step explanation:

The order is important, which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

4 items from a set of 7, so:

P_{(7,4)} = \frac{7!}{(7-4)!} = 7*6*5*4 = 840

840 ways.

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