Going by the data given, the best center of distribution to use in terms of mean and median is D) Mean for Bakery A because the data is symmetric; median for Bakery B because the data is not symmetric.
<h3>What centers of distribution should be used?</h3>
The mean should be used for data sets that are symmetric while the median should be used for data that is not symmetric.
The data is said to be symmetric when the mean and median are equal or very close.
Bakery A mean:
= (45 + 52 + 51 48 + 61 + 34 + 55 46) / 8
= 49
Bakery A median is 49.5
Bakery B mean:
= (48 42 + 25 45 + 57 + 10 + 43 + 46 ) / 8
= 39.5
Bakery B median is 44.
This shows that Bakery A data is symmetric so the best center of distribution to use is mean.
Bakery B is not symmetric so the center of distribution to use is median.
Find out more on symmetric data at brainly.com/question/7130507
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6= mx+b
6-b=mx
x=(6-b)/m
hope you understand
Answer:
x = 1, y = 6
or
x = 5, y = 2.
Step-by-step explanation:
y=x2−7x+12
y=−x+7
Substitute for y in the first equation:
- x + 7 = x^2 - 7x + 12
x^2 - 7x + x + 12 - 7 = 0
x^2 - 6x + 5 = 0
(x - 1)(x - 5) = 0
x = 1, 5.
When x = 1, y = -1 + 7 = 6.
when x = 5, y = -5+7 = 2.
Answer:
162
Step-by-step explanation:
18 + 63 + 81
First, turn 12 percent into decimal which is .12
Of = multiple
So now you times .12 times 91 which is 10.92
Answer 10.92
Hope this help
