We use the distance formula for this problem.
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
The distance between point (-2,-2) and point (-2,4).
d = √[(⁻2 - ⁻2)² + (4 - ⁻2)²] = 6 units
Then, compute for 20% of 6 units:
Distance traveled = 6(0.2) = 1.2 units
Use 1.2 units as distance and the starting point (-2,-2). The x-coordinate should still be at -2 because the distance is a straight line as shown in the picture.
1.2 = √[(-2 - ⁻2)² + (y - ⁻2)²]
Solving for y,
y = -0.8
The point is found at (-2,-0.8). This is located at quadrant 3. As to the distance traveled, that would be: 1.2*6 = 6 miles. Thus, the answer is C.
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data, 
= 5.5 mins
Standard deviation, 
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒ 
...raw score,
= 
⇒ Plugging the values.
⇒ 
⇒ 
For raw score 5.5 the z score is.
⇒ 
⇒ 
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒ 
⇒ 
and 
.<em>..from z -score table.</em>
⇒ 
⇒ 
To find the percentage we have to multiply with 100.
⇒ 
⇒ 
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
It is not a negative so it is 10 because the number can't be big
The cosine is -0.88
This is rounded from <span>-0.88387747318
The sine is .48.
This is rounded from </span><span>0.46771851834</span>
