after taking sqrt both side
3x/
3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y
Answer is A
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after taking sqrt both side
3x/
3x/3y√2
x/√2y
multiply both denomenator and numerator by√2
√2x/2y
Answer is A
Answer:
Please check the explanation.
Step-by-step explanation:
Given the sequence
2, 6, 10, 14, 18
An arithmetic sequence has a constant difference and is defined as
compute the differences of all the adjacent terms
The difference between all the adjacent terms is the same.
Thus,
and
Therefore, the nth term is computed by:
Thus, position to term rule of 2, 6, 10, 14, 18 multiply by __4___ and subtract by __2__.
Answer:
Step-by-step explanation:
(f*g)(x) = (-5x² + 2x + 7) (x +1)
= x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)
= x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7
= -5x³ + 2x² + 7x - 5x² + 2x + 7
= - 5x³ + <u>2x² -5x²</u> <u>+ 7x + 2x </u>+7 {Combine like terms}
= -5x³ - 3x² + 9x + 7
4) (f*g)(x) = (x² + 2x + 4)(x - 2)
= x*(x² + 2x + 4) - 2*(x² + 2x + 4)
= x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4
= x³ + 2x² + 4x -2x² -4x - 8
= x³ - 8