The student council started with 50 cans of food for the food drive and then

Mathematics

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AlladinOne [14]2 years ago

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10 students is that what your looking for

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A projectile is fired at 571 mi hr. How fast is that in meters per second to the nearest whole value? Use the conversion factor

ELEN [110]

Answer:

Consider this: factors that are the same that are in the numerator and denominator of a fraction cancel out.

e.g. 20/30 = [2(10)]/[3(10)] = 2/3 This is because the 10 present in the numerator exactly equals the 10 present in the denominator.

We can use the above principle for these types of problems!

If the projectile is fired at 422 mi/hr, and we want to convert this speed into m/s, we just need to go through the following process:

422 mi/hr * 1610m/1mi * 1hr/60min * 1min/60s = 189 m/s

Step-by-step explanation:

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2 years ago

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Write 230.251 in expanded form

Tamiku [17]

200+30+0.2+0.05+0.001=230.251

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2 years ago

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$