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Leto [7]
3 years ago
13

How many molecules are equal to 89.23g of calcium oxide

Chemistry
2 answers:
bekas [8.4K]3 years ago
8 0

Answer:

1.593 moles

Explanation:

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

Mila [183]3 years ago
5 0

Answer:

9.64 × 10²³ molecules

Explanation:

Given data:

Mass of calcium oxide = 89.23 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of calcium oxide.

Number of moles = mass/molar mass

Number of moles = 89.23 g/ 56.1 g/mol

Number of moles = 1.6 mol

Number of molecules;

1 mole contain 6.022 × 10²³ molecules

1.6 mol × 6.022 × 10²³ molecules / 1mol

9.64 × 10²³ molecules

The number 6.022 × 10²³ is called Avogadro number.

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The current global population is 7.7 billion people, and the WHO estimates the minimum water need per person per day is 15 L. An
anygoal [31]

Answer:

a) The amount of freshwater available as groundwater, lakes and rivers, does not even reach one day the need for consumption for the current global population.  ( t = 5.489 E-13 day )

b) The annual terrestrial precipitation, reaches to sustain the drinking water needs for the current global population

Explanation:

Let P = 7.7 billion people = 7.7 E12 person

∴ water needed for the total population for one day:

⇒ water amount  = 7.7 E12 person * ( 15 L / person. day ) = 1.155 E14 L H2O /day

⇒ water amount = 1.155 E14 L H2O/day * 1 E1 Km² H2O / L H2O = 1.155 E15 Km² H2O/day * ( 365 day / year ) = 4.216 E17 Km²/year

∴ freshwater available:

freshwater = 6.34 E2 Km² H2O

how long will this water sustain the current population?

⇒ t = 6.34 E2 Km² * day / 1.155 E15 Km² = 5.489 E-13 day

this amount of freshwater does not even meet the need of the current global population.

∴ the annual terrestrial precipitation (Py) = 505000 Km³/year..........from literature

⇒ Py = 505000 Km³ H2O/year * ( 1000 m/Km )³ * ( 1000L/m³ )

⇒ Py = 5.05 E17 L H2O/year * ( 1 E1 Km² / L ) = 5.05 E18 Km² H2O/year

⇒ Py > water amount

the annual terrestrial precipitation of water, reaches to sustain the drinking water needs.

4 0
3 years ago
118g of o2 gas is held at STP what is the volume of gas
shutvik [7]

Answer:

At STP one mole of any gas occupies a volume of 22.4 L: this is the molar volume.

Explanation:

4 0
4 years ago
QUESTION 4
Nikolay [14]

Answer:

False

Explanation:

According to kinetic molecular theory, all collisions are perfectly elastic and energy is conserved.

3 0
3 years ago
Is it Nephrons or Kidney or Urine or Urethra
UkoKoshka [18]

Answer:

it's urine option ( C ) .

7 0
4 years ago
At 25.0 °C the Henry's Law constant for sulfur hexafluoride (SP) gas in water is 2.4x 10 M/atm Calculate the mass in grams of SF
Dmitry_Shevchenko [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass is m =  0.0349 \ g

Explanation:

From the question we are told that

   The Henry's Law constant is  k = 2.4 *10^{10} M/atm

   The volume of water is V = 525 \ ml = 0.525 \ L

   The partial pressure is  P =  1.90 \ atm

   The temperature is T  = 25 ^oC

Henry's  law is mathematically represented as

       C  = P * k

Where C is  the concentration of sulfur hexafluoride(SP)

substituting value

        C = 1.90 * 2.4*10^{-4}

        C = 4.56*10^{-4} \ M

The number of moles of  SP is mathematically represented as

        n = C * V

substituting value

       n =  0.525 * 4.56*10^{-4}

       n =  2.39 *10^{-4} \ moles

The mass of SP that dissolved is

          m = n * Z

Where Z is the molar mass of SP which has a constant value of

           Z = 146 g/mole

So

         m =  2.394*10^{-4} * 146

         m =  0.0349 \ g

6 0
3 years ago
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