The mass of sodium chloride at the two parts are mathematically given as
- m=10,688.18g
- mass of Nacl(m)=39.15g
<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>
Generally, the equation for ideal gas is mathematically given as
PV=nRT
Where the chemical equation is
F2 + 2NaCl → Cl2 + 2NaF
Therefore
1.50x15=m/M *(1.50*0.0821)
1-50 x 15=m/58.5 *(1.50*0.0821)
m=10,688.18g
Part 2
PV=m'/MRT
1*15=m'/58.5*0.0821*273
m'=39.15g
mass of Nacl(m)=m'=39.15g
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Jackie is the fastest student. (Option A)
Explanation:
- From the table it was understood that their speeds are given in meter per second, that is how many meters they run in one second. It was again shown that Jackie's race speed is 5.3 meter per second and all the other three namely Jeremy's speed is 3.9 meter per second, Mike's speed is 4.1 meter per second and finally Niki's speed is 3.8 meter per second.
- So, by comparing with others Jackie is the fastest runner in that race.
True because molo means two so you would need more than 1 atom
Methane composes most of the natural gas.
Explanation:
As the charge of all electrons are equal, the repulsive force exerted by each of them is also going to be equal. So, as K has more electrons repulsing its valence electron than Na, it has greater electron shielding.
