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3 years ago

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1 answer:

Tamiku [17]3 years ago

7 0

Answer:

a or d

Step-by-step explanation:

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What is the smallest of three consecutive positive integers if the product of the smaller two integers is 10 more than 4 times t

r-ruslan [8.4K]

The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8

X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0

( X+3)(X-6)
X=-3. X=6
Don't use the negative

Check 6(7)= 4(8)+10
42=42

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3 years ago

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lora16 [44]

0 bcz modulas function every negative no. in positive
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3 years ago

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Dmitriy789 [7]

Answer:

D

Step-by-step explanation:

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3 years ago

The midpoint of (3 x, -2) and (-4, 5y) is (1,4). find x, -y

Mariana [72]

Answer:

(x,-y): (2,-2)

Step-by-step explanation:

M=(x+x)/2,(y+y)/2

Given (1,4)=

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This implies:

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In a similar way,

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The question demanded (x,-y)

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3 years ago

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