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irakobra [83]
3 years ago
7

The setup in the diagram is left outside during the day and night . Bubbles are continuously produced regardless of the presence

of sunlight.what can you predict of the composition in the bubbles
A. The bubbles are always O2
B. The bubbles are always carbon dioxide CO2
C. During the day the bubbles are CO2 and in the night O2
D. During the day they are O2 and in the night CO2
Chemistry
1 answer:
Angelina_Jolie [31]3 years ago
6 0

Answer:

A

Explanation:

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How many molecules are present in a drop of ethanol, c2h5oh, of mass 2.3*10^-2.3g? (NA=6.0*10^23mol^-1)
sdas [7]

Answer:

3.0 × 10²⁰ molecules

Explanation:

Given data:

Mass of ethanol = 2.3 × 10⁻²°³ g

Number of molecules = ?

Solution:

Number of moles of ethanol:

Number of moles = mass/ molar mass

Number of moles = 2.3 × 10⁻²°³ g / 46.07 g/mol

Number of moles = 0.05 × 10⁻²°³ mol

Number of molecules:

One mole = 6.022 × 10²³ molecules

0.05 × 10⁻²°³ mol  ×  6.022 × 10²³ molecules / 1 mol

0.30 × 10²⁰°⁷ molecules

3.0 × 10¹⁹°⁷ molecules which is almost equal to 3.0 × 10²⁰ molecules.

5 0
3 years ago
Consider the diagram below
Artyom0805 [142]
Energy of the reactants would be correct
5 0
2 years ago
a liquid that boils at a low temperature and evaporates rapidly at room temperature is describe as being
Sunny_sXe [5.5K]

Answer: Volatile

Explanation:

like ethanol(alcohol) it evaporates when you put it in the hand, really fast.

Some people think that it dries when it really evaporated at room temperature from liquid to gas

5 0
3 years ago
Help!! < PHYSICAL SCIENCE>
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The answer is B or the second answer
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3 years ago
Calculate the volume, in milliliters, for the following:
fredd [130]

Answer: The volume for 0.850 mol of NaNO_{3} from a NaNO_{3} solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

  • As given moles of NaNO_{3} are 0.850 mol and molarity of NaNO_{3} solution is 0.5 M. Hence, its volume is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL

Therefore, the volume for 0.850 mol of NaNO_{3} from a NaNO_{3} solution is 1700 mL.

  • As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol

So, volume for LiOH solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

6 0
3 years ago
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