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JulijaS [17]
2 years ago
13

Which is an example of an instinct?

Chemistry
1 answer:
kompoz [17]2 years ago
5 0

Answer:

An innate, typically fixed pattern of behavior in animals in response to certain stimuli.

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In Males which of the following organ performs a dual function of ejaculation of sperm and voiding of urine
Anna11 [10]
I believe it is the urethra 
3 0
3 years ago
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If the strength of the magnetic field at A is 10 units, the strength of the magnetic field at B is _____. 640 units 6.4 units 2.
dezoksy [38]
Answer : Option C) 2.5 units

Explanation : For calculating the strength of a unknown magnetic field in comparison with the given magnetic field we can use the magnetic formula as;

\frac{ S_{1}}{S_{2}} =  \frac{ (D_{1}^{2}) }{(D_{2}^{2})} .

On substituting the values we get; 

\frac{10}{x}  =  \frac{4^{2}}{2^{2}} ;

On solving we get the magnetic B field strength as 2.5 units


4 0
3 years ago
Read 2 more answers
1.name the gas produced by the reaction between calcium carbonate and dilute hydrochloric acid?
GuDViN [60]
I dont know anything about this since i am not in college or high school i am in Middle school but I hope I will learn it
4 0
3 years ago
The Molar mass(M.w) in g/mol of 6.3 grams of an ideal gas that placed in 5.0 L tank at ST
BigorU [14]

Answer:

28 g/mol, N2

Explanation:

Given data:

Volume of gas = 5.0 L

Mass of gas = 6.3 g

Pressure = 1 atm

Temperature = 273 K

Molar mass of gas = ?

Solution:

We will calculate the density first.

d = mass/ volume

d = 6.3 g/ 5.0 L

d = 1.26 g/L

Molar mass:

d = PM/RT

M = dRT/P

M =  1.26 g/L× 0.0821 atm.L/mol.K × 273 K/ 1 atm

M = 28 g/mol

Molar mass of N₂ is 28 g/mol thus given gas is N₂.

7 0
2 years ago
Combustion analysis of 0.300 g of an unknown compound containing carbon, hydrogen, and oxygen produced 0.5213 g of co2 and 0.283
Lyrx [107]
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
                                        = 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
                                                 =0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
                          =  0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16) 
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2 
∴ the emprical formula C3H8O2
           



6 0
3 years ago
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