<u>Answer:</u> The correct answer is 1.18 g.
<u>Explanation:</u>
We are given a chemical equation:
We know that at STP conditions:
22.4L of volume is occupied by 1 mole of a gas.
So, 2.21L of carbon dioxide is occupied by = 
of carbon dioxide gas.
By Stoichiometry of the above reaction:
1 mole of carbon dioxide gas is produced by 1 mole of carbon
So, 0.0986 moles of carbon dioxide is produced by = 
of carbon.
Now, to calculate the mass of carbon, we use the equation:
Moles of carbon = 0.0986 mol
Molar mass of carbon = 12 g/mol
Putting values in above equation, we get:
Hence, the correct answer is 1.18 g.
Answer: m= 3.15x10-3 g NaHCO3
Explanation: To find the mass of NaHCO3 we will use the relationship between moles and molar mass. The molar mass of NaHCO3 is 84 g.
3.75x10-5 moles NaHCO3 x 84 g NaHCO3 / 1 mole NaHCO3
= 3.15x10-3 g NaHCO3
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To find the acceleration given the net force (N) and the mass (kg), we will need to use Newton's Second Law of Motion, which is shortened to be F = ma.
In this formula, F is the net force, m is the mass, and a is the acceleration.
Since we are given the net force and mass, we will be using division to find the acceleration, which is measured as m/s².
1). Net Force: 5.0 N; Mass = 2.5 kg
5.0 N / 2.5 kg = 2.0 m/s²
2). Net Force: 2.32 N; Mass = 12 kg
2.32 N / 12 kg ≈ 0.19 m/s²
3). Net Force: 18.2 N; Mass: 1.967 kg
18.2 N / 1.967 kg ≈ 9.25 m/s²
4). Net Force: 0.87 N; Mass: 21.2 kg
0.87 N / 21.2 kg ≈ 0.04 m/s²
5). Net Force: 180 N; Mass: 1.793 kg
180 N / 1.793 kg ≈ 100.39 m/s²
<u>Final answers</u>:
- 2.0 m/s²
- 0.19 m/s²
- 9.25 m/s²
- 0.04 m/s²
- 100.39 m/s²
