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Kisachek [45]
3 years ago
10

4 .subtract the H.C. F of 8, 12 and 16 From the H.C. F OF 14 and 28.

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

HCF 8, 12, 16 = 4

HCF 14, 28 = 14

14 - 4 = 10

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Cost of an airplane flight increase from $250 to $260. What is the percentage increase?​
Sedaia [141]

Answer:

Solution given:

Increase percentage=\frac{260-250}{250}*100%

=4%

<u>the percentage </u><u>increase</u><u> </u><u>is</u><u> </u><u>4</u><u>%</u><u>.</u>

3 0
3 years ago
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For what values of h and k does the linear system have infinitely many solutions? 2x1 + 5x2 = −1 hx1 + kx2 = 7
Kruka [31]

Answer:

The values of h and k for a linear system with infinitely many solutions are -2 and 5, respectively.

Step-by-step explanation:

Let 2\cdot x_{1}+5\cdot x_{2} = -1\cdot h\cdot x_{1} + k\cdot x_{2} = 7, if this linear system has infinitely many solutions, then the following conditions must be met:

-1\cdot h = 2 and k = 5.

h = -2 and k = 5

The values of h and k for a linear system with infinitely many solutions are -2 and 5, respectively.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t
Darina [25.2K]

Answer:

12

Step-by-step explanation:

\sqrt{12} \times\sqrt{12}

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0

\sqrt{12}\sqrt{12}=12

=12

7 0
3 years ago
Please answer properly.
madreJ [45]

Answer:

1) y=-6

2)x=3

3) y=8

4)a=8

Step-by-step explanation:

4y+24=0

subtract 24 from both sides

4y=-24

divide both sides by 4

y=-6

---------->>>>

15+3=6x

combine like terms

18=6x

divide both sides by 6

3=x

---------->>>>

9y-72=0

add 72 to both sides

9y+72

divide both sides by 9

y=8

---------->>>>

8a=75-11

combine like terms

8a=64

divide both sides by 8

a=8

--------------------------------------------

Hope this is helpful.

8 0
3 years ago
Read 2 more answers
Solve and solve work please
nikitadnepr [17]

Answer:

6 but if it this _ 1 okrrrrrrrrr

4 0
3 years ago
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