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3 years ago

12

Please answer properly.

2 answers:

madreJ [45]3 years ago

8 0

Answer:

$1) y=-6$

$2)x=3$

$3) y=8$

$4)a=8$

Step-by-step explanation:

$4y+24=0$

subtract 24 from both sides

$4y=-24$

divide both sides by 4

$y=-6$

---------->>>>

$15+3=6x$

combine like terms

$18=6x$

divide both sides by 6

$3=x$

---------->>>>

$9y-72=0$

add 72 to both sides

$9y+72$

divide both sides by 9

$y=8$

---------->>>>

$8a=75-11$

combine like terms

$8a=64$

divide both sides by 8

$a=8$

--------------------------------------------

Hope this is helpful.

earnstyle [38]3 years ago

5 0

The answer is y=-6,x=3,y=8 a=8

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2 years ago

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3 years ago

Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.

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And the Sum of Squared Errors (SSE) for the clustering result is 378

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second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

the points will be clustered according to their distance to the centroids.
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1) <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

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first cluster (6,12) mean:9

second cluster (18,24,30,42,48) mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

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second cluster (30,42,48) mean:40

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second cluster (30,42,48) mean:40

Sum of Squared errors = $(15-6)^{2}$ + $(15-12)^{2}$ + $(15-18)^{2}$ + $(15-24)^{2}$ + $(40-30)^{2}$ + $(40-42)^{2}$ + $(40-48)^{2}$ =348

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