The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
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Answer:
B,D
Step-by-step explanation:
the independent variable is what is being changed or manipulated and he is changing how many plays he gets. the amount of yards he gets is a result of the amount of plays so thats the dependent variable.
All rhombuses have 2 pairs of parallel sides.
first you have to look to the right of that number .check if it is more than 5. if it is ,than add one to the first digit in the quotient. all the other numbers will turn to zeroes.
0 remainder of 6
Hope this helps