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alexandr1967 [171]
3 years ago
8

PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!
SHOW THE WORK PLEASEEEE!!!

Mathematics
2 answers:
Anna11 [10]3 years ago
5 0

Answer:

0 the answer

i hope its help

thats the right answer

SOVA2 [1]3 years ago
5 0
I think

−3 x^2 y^3 z^2 * -17 x^3 z^4

-(3 * -17) x^2 x^3 y^3 z^3 z^4

-(-51) x^2 x^3 y^3 z^2 z^4

-(-51x^2 x^3 y^3 z^2 z^4)

-(-51 x^5 y^3 z^2+4)

-(-51 x^5 y^3 z^6 )

51 x^5 y^3 z^6
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HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION RQ!!!!!!!!
Ilya [14]

Answer:

the answer is A i hope this helps you! may i have brainly?:)

Step-by-step explanation:

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3 years ago
Find the zeros of f(x) =x^3+2x^2-3x
lora16 [44]

Answer: 0, 1, -3

Step-by-step explanation:

f(x) = x^3 +2x^2 -3x

f(x) = x(x^2 +2x-3)

f(x) = x(x-1)(x+3)

to find zeroes, plug into f(x) and solve for each value of x. doing this gives 0, 1, and -3

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3 years ago
An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the
DedPeter [7]

<em><u>The inequality can be used to find the interval of time taken by the object to reach the height  greater than 300 feet above the ground is:</u></em>

d = -16t^2 + 1000

<em><u>Solution:</u></em>

<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the  formula:</u></em>

d = -16t^2 + 1000

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

-16t^2 + 1000 > 300

Solve the inequality

Subtract 1000 from both sides

-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700

16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61

Time cannot be negative

Therefore,

t < 6.61

And the inequality used  is: -16t^2 + 1000>300

6 0
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What is the product of 349 and 74?​
jekas [21]

Answer:

423

Step-by-step explanation:

349+74=423

4 0
3 years ago
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PLEASE HELP!! WILL GIVE BRAINLIEST!!
schepotkina [342]

Answer:

Please find attached pdf

Step-by-step explanation:

Download pdf
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