Write the equation of the line that passes through the points (0, 3) and (2. 6)
1 answer:
Answer:
Y=3/2X + 3
Step-by-step explanation:
Y= mX + b
b is the y intercept or the Y number for when the point is in place o for X
(0, 3) is the Y intersect so b is 3
this is shown on the diagram I drew below
m is the slope of the line and can be calculated
m = change in Y/ Change in X
Our change in Y is 6-3
And out change is X is 2-0
So
m = 3/2
This is shown on the image below
Y=3/2X + 3
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Answer:
2a: (c)
5o: (1, 3) and (1,1)
3a: (b)
1a: (d)
4o: (b)
Step-by-step explanation:
2a: the equation of a circle circumference needs to be transformable to the form where
is the center and <em>r</em> is the radius. (a) and (d) can’t be it because they contain non-zero factors on <em>xy</em>. (b) isn’t an equation.
5o: just put the given (<em>x</em>, <em>y</em>) into the equations and see if it holds. (2, 3) isn’t on the circumference of (1) because , (3, 1) isn’t on it either because
.
3a: calculate the value of the left-hand side term of the equation using (<em>x</em>, <em>y</em>) from the given point <em>M</em>. That’s the difference of square distance to the center to the square radius . Thus it’s 0 if the point is on the circumference, negative if inside and positive if outside. You get
, positive, so it’s outside the circle.
1a: see definition from 2a. Here, .
4o: insert the y from the straight line equation (r) (which can be equivalently transformed to ) into the circumference equation. If it yields no solution, that’s outside, it there’s exactly one solution, that’s a tangent and if there are two solutions, it’s a secant.
There are two solutions, so it’s a secant.