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3 years ago

8

A ball tied on a string rotates in a circular path as shown above. The only forces acting on the ball at any point are the weigh

t and of the string. What is the equation for the net centripetal force at point C?

1 answer:

Harlamova29_29 [7]3 years ago

6 0

Answer:

the third one T-W

Explanation:

the direction of the Tension and weight are opposite

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The sound intensity from a jack hammer breaking concrete is 2.0W/m2 at a distance of 2.0 m from the point of impact. This is suf

kupik [55]

Answer:

(a) $I_{1}=3.2*10^{-3}W/m^{2}$

(b) $\beta =95dB$

Explanation:

Given data

Distance r₁=50 m

Distance r₂=2 m

Intensity I₂=2.0 W/m²

To find

(a) The Sound Intensity I₁

(b) The Sound Intensity level β

Solution

For (a) the Sound Intensity I₁

$\frac{I_{1} }{I_{2}}=\frac{(r_{2})^{2} }{(r_{1})^{2} }\\I_{1} =I_{2}(\frac{(r_{2})^{2} }{(r_{1})^{2} })\\I_{1}=(2.0W/m^{2} )(\frac{(2m)^{2} }{(50m)^{2} })\\I_{1}=3.2*10^{-3}W/m^{2}$

For (b) the Sound Intensity level β

The Sound Intensity level β is calculated as follow

$\beta =(10dB)log_{10}(\frac{I}{I_{o} } )\\\beta =(10dB)log_{10}(\frac{3.2*10^{-3}W/m^{2} }{1.0*10^{-12} W/m^{2} } )\\\beta =95dB$

8 0

3 years ago

Whats the answer<br> ----------------------------

GenaCL600 [577]

Answer:

repel each other

Explanation:

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8 0

3 years ago

A penny is placed on a rotating turntable. Where on the turntable does the penny require the largest centripetal force to remain

Artyom0805 [142]

Answer:

m = mass of the penny

r = distance of the penny from the center of the turntable or axis of rotation

w = angular speed of rotation of turntable

F = centripetal force experienced by the penny

centripetal force "F" experienced by the penny of "m" at distance "r" from axis of rotation is given as

F = m r w²

in the above equation , mass of penny "m" and angular speed "w" of the turntable is same at all places. hence the centripetal force directly depends on the radius .

hence greater the distance from center , greater will be the centripetal force to remain in place.

So at the edge of the turntable , the penny experiences largest centripetal force to remain in place.

Explanation:

5 0

3 years ago

A spring has a spring constant of 800 N/m. How much work must be done to stretch the spring 0.4 m from its unstretched position?

Sunny_sXe [5.5K]

Answer:

A. 64.0 J

Explanation:

Given parameters:

Spring constant = 800N/m

Extension = 0.4m

Unknown:

Work done = ?

Solution:

The work done in a string is given as:

Work done = $\frac{1}{2}$ x 800 x 0.4² = 64J

8 0

3 years ago

students make a small elevator machine with 5 kg and 10 kg masses on either side how fast will the masses accelerate once they a

mihalych1998 [28]

Answer:

The acceleration of the elevator machine is, a = 3 m/s²

Explanation:

Given data,

The mass on the one end, m = 5 kg

The mass on the other end, M = 10 kg

According to the Atwood's machine

Ma = Mg - T

ma = T - mg

Adding those equations,

a (M + m) = g ( M - m)

a = (M + m) / ( M - m)

Substituting the values,

a = (10 + 5) / (10 - 5)

= 3 m/s²

The acceleration of the elevator machine is, a = 3 m/s²

8 0

3 years ago