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mr_godi [17]
3 years ago
14

5. A 6.0-kilogram mass is moving with a speed of 2.0 m/s. What is the kinetic energy of the mass?

Physics
1 answer:
Ann [662]3 years ago
3 0

Answer:

K.E. = ½ × mv²

= ½ × 6 × (2)²

= ½ × 6 × 4

= 3 × 4

= 12 J

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Which of the following is an example of a projective test?
IceJOKER [234]

Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).

Some examples of projective tests are the Rorschach Inkblot Test, the Thematic Apperception Test (TAT), the Contemporized-Themes Concerning Blacks test, the TEMAS (Tell-Me-A-Story), and the Rotter Incomplete Sentence Blank (RISB).

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3 years ago
The figure above shows the net force exerted on an object as a function of the position of the object. The object starts from re
weqwewe [10]

Answer:

0.06 Kg

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Net Force (F) = 3 N

Mass (m) =?

Next, we shall determine the acceleration of the object. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 3.0 m/s

Distance (s) = 0.09 m

Acceleration (a) =?

v² = u² + 2as

3² = 0² + (2 × a × 0.09)

9 = 0 + 0.18a

9 = 0.18a

Divide both side by 0.18

a = 9 / 0.18

a = 50 m/s²

Finally, we shall determine the mass of the object. This can be obtained as follow:

Net Force (F) = 3 N

Acceleration (a) = 50 N

Mass (m) =?

F = ma

3 = m × 50

Divide both side by 50

m = 3 / 50

m = 0.06 Kg

Therefore, the mass of the object is 0.06 Kg

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2 years ago
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3 years ago
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An AC generator consists of 20 circular loops of wire with an area of 75 cm2. It has a maximum induced voltage of 24 V. If its a
Monica [59]

Faraday's law allows us to find the magnetic field that produces the emf in the rotating system is:

  • The magnetic field is:  B = 0.424 T

Faraday's law of induction states that when the magnetic flux changes in time, an induced electromotive force is produced.

            fem = - \frac{d \Phi_B }{dt}  

where fem is the induced electromotive force and Ф the flux,

The magnetic flux is the scalar product of the field and the area.

           \Phi_B = B . A = B A  \ cos \theta  

In this case we have several turns, so the expression remains.

           fem = - N B A \ \frac{d cos \theta}{dt}  

Indicate that the turns rotate at a constant frequency, therefore we can use the uniform rotational motion ratio.

           

           θ = w t

We substitute

 

         fem = - N B A \ \frac{d \ cos \ wt}{dt}\\fem =  N B A w sin \ wt

the maximum induced electromotive force occurs when the sine function is ±1

          fem = N B A w

They indicate that the fem = 24 V, the number of the turn is N = 20, the area is A = 75 cm² = 75 10⁻⁴ m² and the frequency f = 60 Hz

Frequency and angular velocity are related.

           w = 2π f

We substitute.

           fem = N B A 2π f

           B = \frac{fem }{2 \pi \ NA \ f}  

Let's calculate.

         B= \frac{24 }{2\pi \ 20 \ 75 \ 10^{-4} 60}B = 24 / 2pi 20 75 10-4 60

         B = 0.424 T

In conclusion, using Faraday's law we can find the magnetic field that produces the emf in the rotating system is:

  • The magnetic field is; B = 0.424 T

Learn more about Faraday's law here:  brainly.com/question/24617581

8 0
2 years ago
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