Answer:
u= 755 m/s
Explanation:
Lets take
Velocity of bullet = u m/s
The velocity of system after collision ,v= 5 m/s
m= 10 g = 0.01 kg
M= 1.5 kg
From linear momentum conservation( because there is no any external force on the system)
Pi= Pf
m u = ( m +m) v
0.01 x u= (1.5 + 0.01) x 5
u= 755 m/s
Answer:
1120 N
Explanation:
The velocity with which he hits the water can be found with kinematics:
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)
v = -13.3 m/s
Or it can be found with conservation of energy.
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × -9.8 m/s² × -9.00 m)
v = -13.3 m/s
Sum of forces on the diver after he hits the water:
∑F = ma
F − mg = m Δv/Δt
F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)
F = 1120 N
Answer:
Explanation:
The equation of electric field is
E = 375 Sin(5.97 x 10^15 t + 1.99 x 10^7 x)
Compare with the standard equation
E = Eo Sin(ωt + kx)
(b) Amplitude of electric field, Eo = 375 V/m
Amplitude of magnetic field, Bo = Eo / c = 375 / (3 x 10^8)
Bo = 125 x 10^-8 Tesla
Bo = 1.25 x 10^-6 Tesla
(c) ω = 5.97 x 10^15 rad
2 x 3.14 x f = 5.97 x 10^15
f = 0.95 x 10^15 Hz
f = 9.5 x 10^14 Hz
.........,....,,,???........