Write the first five terms in the sequence defined by the explicit formula

Mathematics

2 answers:

Bas_tet [7]3 years ago

7 0

Answer: A

-1,2,7,14,23

SOVA2 [1]3 years ago

6 0

Answer:

D) -2, -1, 2, 7, 14

Step-by-step explanation:

Let's take the first five whole numbers.

0, 1, ,2, 3, 4

Now plug in n =1 in the explicit formula An = n^2 -2

When n = 0,

A0 = (0)^2 - 2 0 - 2= -2

When n = 1,

A1 = (1)^2 - 2 = 1 - 2 = -1

When n = 2,

A2 = (2)^2 - 2 = 4 - 2 = 2

When n = 3,

A3 = (3)^2 - 2 = 9 - 2 = 7

When n = 4,

A4 = (4)^2 - 2 = 16 - 2 = 14

Therefore, the first five terms are -2, -1, 2, 7, 14

Thank you.

You might be interested in

4x^2-5x-15=0 how to find the vertex and y intercept

mezya [45]

$ax^2+bx+c=0\\\\the\ vertex:\left(\frac{-b}{2a};\frac{-(b^2-4ac)}{4a}\right)\\\\y-intrcept=c\\=======================================\\\\4x^2-5x-15=0\\\\a=4;\ b=-5;\ c=-15\\\\\frac{-b}{2a}=\frac{-(-5)}{2\cdot4}=\frac{5}{8};\ \frac{-(b^2-4ac)}{4a}=\frac{-[(-5)^2-4\cdot4\cdot(-15)]}{4\cdot4}=-\frac{265}{16}\\\\\boxed{the\ vertex:\left(\frac{5}{8};-\frac{265}{16}\right)}\\\\\boxed{y-intercept:-15}$