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3 years ago

Vertex:____________________________

Mathematics

1 answer:

Pani-rosa [81]3 years ago

8 0

Answer:

The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. ... The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For a quadratic function in standard form, y=ax2+bx+c , the axis of symmetry is a vertical line x=−b2a .

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Find the area of the largest circle that can be inscribed inside a square whose diagonal is 5" ( with explanation )

sweet-ann [11.9K]

Answer:

19.625

Step-by-step explanation:

If the square's diagonal is 5 and the circle is inscribed in it, that means that the radius is 2.5

2.5^2*3.14

=19.625

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3 years ago

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Determine which equation represents the following relationship:

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Brainliest question Please help me now plz

Novosadov [1.4K]

Answer:

A. Inside the circle

Step-by-step explanation:

K(0, 0), U (6, - 4), V ( $\sqrt 2,\: 7)$

In order to determine whether point V lie inside, outside or on the circle, first we will find the distances between points K & U and then K & V.

KU would be radius of the circle.

If KV is smaller than KU, then V will lie inside.
If KV is larger than KU, then V will lie outside
And If KV = KU, then V will lie ion the circle.

$d(KU) = \sqrt{ {(6 - 0)}^{2} + {( - 4 - 0)}^{2} } \\ = \sqrt{ {6}^{2} + {( - 4)}^{2} } \\ = \sqrt{36 + 16} \\ \red{ \bold{ d(KU)= \sqrt{52} }} \\ \\ d(KV) = \sqrt{ {( \sqrt{2} - 0)}^{2} + {( 7 - 0)}^{2} } \\ = \sqrt{ {( \sqrt{2)} }^{2} + {(7)}^{2} } \\ = \sqrt{2 + 49} \\ \purple{ \bold{ d(KV)= \sqrt{51} }} \\ \\ \because \: d(KU) > d(KV) \\$

Hence point V lie inside of the circle.

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3 years ago