Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
A. The description represents an arithmetic sequence because the successive y-values have a common difference of 600
Step-by-step explanation:
The equation that this situation is describing would be
This would mean that this equation would be an arithmetic series
B becuase if you divide the rise over run you get 45 which is the correct answer.
hope this helps
-turtles12345
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
b=7.1¯6−2f/3
Isolate the variable by dividing each side by factors that don't contain the variable.
f=10.75−3b/2
Step-by-step explanation:
