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3 years ago

Please helppp meeeee do thissss

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

8 0

Answer:

x=7

I hope it's help you

katen-ka-za [31]3 years ago

6 0

Answer:

Step-by-step explanation:

8x = 56

x = 56 ÷ 8

x = 7

hope it will help

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Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou

Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

$x=z+136$

We also know that Y weighs 117 pounds more than car Z, this can be express as:

$y=z+117$

Finally, we know that the total weight of all the cars is 9439, then we have:

$x+y+z=9439$

Hence, we have the system of the equations:

$\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}$

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

$\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}$

Now that we have the value of z we plug it in the first two equations to find x and y:

$\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}$

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0

1 year ago

Find the values of the 30th and 90th percentiles of the data. Please show your work.

MaRussiya [10]

Answer:

30th percentile:109

90th percentile: 188

Step-by-step explanation:

The given data set is:

129, 113, 200, 100, 105, 132, 100, 176, 146, 152

We arrange the data set in ascending order to obtain;

Array= $100,100,105,113,129,132,146,176,200$

The 30th percentile is located at

$(\frac{30}{100}\times 10 )}$ -th position, where n=10 is the number of items in the data set

This implies that the 30th percentile is at the 3rd position.

Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;

This implies that the 30th percentile = $\frac{105+113}{2}=\frac{218}{2}=109$

The 90th percentile is located at

$(\frac{90}{100}\times 10 )}$ -th position, where n=10 is the number of items in the data set

This implies that the 90th percentile is at the 9th position.

Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;

This implies that the 90th percentile = $\frac{176+200}{2}=\frac{376}{2}=188$

6 0

3 years ago

- A picture frame is 12 inches long and 9 inches wide. In inches, what is the diagonal length of

sp2606 [1]

I would say 15 inches

7 0

3 years ago

If I have 150,000 crystals, and ONE costume cost 4,000 crystals, how many costumes can I buy total?

MArishka [77]

Okay, think of it this way:

You have to find how many times 4,000 goes into 150,000.

This will tell you how many costumes you can buy.

To make this easier, we can divide 4 by 150. (this is proportional to 4,000 and 150,000 since we took 3 zeros from each number; you will get the same answer)

150/4= 37.5

You can buy 37 whole costumes.

Hope this helped!

6 0

3 years ago

Please answer the simple math question

Shtirlitz [24]

Answer:

5y - 5b

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers