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3 years ago

-2x + y = 5 what does y equal and how did you solve it?

Mathematics

2 answers:

Olin [163]3 years ago

7 0

Answer:

y=2x+5

Step-by-step explanation:

Let's solve for y.

−2x+y=5

Step 1: Add 2x to both sides.

−2x+y+2x=5+2x

y=2x+5

Mandarinka [93]3 years ago

5 0

Answer:

y = 2x + 5

Step-by-step explanation:

-2x + y = 5 or y -2x = 5

We want what y equals so we need to isloate it. To do this, we need to add2x to both sides. This will cancel the 2x on the left side and now we have y alone. Remember, you have to do it to both sides. Therefore:

y = 2x + 5

Note: This equation is in slope-intercept form, y= mx + b

If this was the equation of a line:

m (slope) = 2

b (y-intercept) = 5

Hope this helps!

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Is it true that for any two nonzero integers the product and quotient have the same sign?

Nataliya [291]

<span>The rule of signs is the same for multiplication and division. Two numbers with the same sign, multiplied or divided, the answer is positive. Two numbers with different signs, multiplied or divided, the answer is negative. </span>

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3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Hey can you please help me with 8 and 10 :)

insens350 [35]

8) So remember the sum of all angles inside a triangle is equal to 180°. We first want to figure out the angle below the 110°.

A straight line is 180° so if we do 180 - 110 we get 70° therefore the angle below the 110° is 70°.

So we now know two angles in the triangle, 70° and 80°. Add these and we get 150°. Now we can determine the final angle (the one labelled (2x - 6)) which will be 30°.

So let’s make it into an equation:

2x - 6 = 30

Add 6 to both sides to isolate 2x:

2x = 36

Divide by 2 to get the value of x:

x = 18

10) Since the sum of all angles in a triangle is 180, and there are only 3 angles, we can determine A easily.

B = 10°
C = 160°

So to determine A:

180 - 160 - 10

Which gives us 10

Therefore A = 10°.

So the answers:

8) x = 18
9) A = 10°

I hope this helps you!!

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Answer:

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Step-by-step explanation:

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