Answer:
The distribution of scores on this final exam is left-skewed.
Step-by-step explanation:
We use the Pearson Mode Skewness to solve this question. It states that:
If the median is higher than the mean, the distribution is left-skewed.
If the median is lower than the mean, the distribution is right-skewed.
If the median is the same as the mean, the distribution is symmetric.
In this problem, we have that:
Median = 74
Mean = 70
Median higher than the mean
So the distribution of scores on this final exam is left-skewed.
I believe it is.... (2,2)or(4,4)
The cheetah runs 2 meters/sec faster than the gazelle. Eventually the cheetah will overcome the gazelle. Since distance = rate times time, time = distance/rate.
Thus,
300 meters / (2 meters/sec) = 150 sec = 2 min 30 sec
Answer:
[0.184, 0.266]
Step-by-step explanation:
Given:
Number of survey n =280
Number of veterans = 63
Confidence interval = 90%
Computation:
Probability of veterans = 63/280
Probability of veterans =0.225
a=0.1
Z(0.05) = 1.645 (from distribution table)
Confidence interval = 90%
So,
p ± Z*√[p(1-p)/n]
0.225 ± 1.645√(0.225(1-0.225)/280)
[0.184, 0.266]
7) y = 4x
8) y = 7x/8
9) y = 25x/3
I think this are the answers.