How many moles of Al(CN)3 are in 227 g of the compound?
1 answer:
Answer: 2.16 moles Al(CN)3
Explanation: To find the number of moles of Al( CN)3 we will use stoichiometry which is the relationship of mole with molar mass.
227 g Al(CN)3 x 1 mole Al(CN)3 / 105 g Al(CN)3
= 2.16 moles Al(CN)3
Cancel out the unit of grams Al(CN)3 and the remaining unit is in moles Al(CN)3.
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