Step

How to identify reasonable domain and range

puteri [66]

Answer:

The domain is the input values on the x-axis and range is input values on the y-axis

Step-by-step explanation:

Basically, domain is the horizontal values and range is the vertical ones.

6 0

3 years ago

Plz help.......................

True [87]

Let's use the slope intercept form of a line which is:

y=mx+b where m=slope and b=y-intercept.

Mathematically m=(y2-y1)/(x2-x1) and the y-intercept is just the value of y when x is equal to zero, where the line intercepts the y axis...

First you want to find the slope by finding two clearly identifiable points on the graph...I'll pick (4,4) and (0,1), now we can calculate the slope or "m"...

m=(4-1)/(4-0)=3/4 so now we can say our line is:

y=0.75x+b, using point (4,4) we can now solve for b.

4=0.75(4)+b

4=3+b

b=1 so the line is"

y=0.75x+1

4 0

4 years ago

Working alone, Dan can do a certain job in three hours and Stan can do the same job in two hours. At these rates, how long would

Liono4ka [1.6K]

Answer:

2 hours and thirty minutes

Step-by-step explanation:

3+2=5

5/2=2.5

4 0

3 years ago

Solving Square Roots Worksheet (x - k)^2 : Part 1

iVinArrow [24]

Answer:

1. x = +/- 2 $\sqrt{2}$ - 7

2. x = $3$ +/- $2i\sqrt{3}$

3. n = $2$ +/- $i\sqrt{2}$

Step-by-step explanation:

1. Divide both sides by 2: (x + 7)^2 = 8

Square root both sides: x + 7 = +/- 2 $\sqrt{2}$

Subtract 7 from both sides: x = +/- 2 $\sqrt{2}$ - 7

2. Square root both sides: x - 3 = $\sqrt{-12}$

Since there is a negative inside the radical, we need to have an imaginary number: $i=\sqrt{-1}$ . So, $\sqrt{-12} =i\sqrt{12} =2i\sqrt{3}$

Add 3 to both sides: x = $3$ +/- $2i\sqrt{3}$

3. Divide by -5 from both sides: (n - 2)^2 = -2

Square root both sides: n - 2 = $\sqrt{-2}$

Again, we have to use i: $n-2=\sqrt{-2} =i\sqrt{2}$

Add 2 to both sides: n = $2$ +/- $i\sqrt{2}$

Hope this helps!

8 0

3 years ago

Read 2 more answers

Numbers 1, and 3 please

Ronch [10]

Answer:

1. shifts the graph right 2 units

2. y = -2(x -3)² +7

Step-by-step explanation:

1) Replacing x with x-h in any function shifts the graph h units to the right. Here, you have replaced x with (x-2), so the graph will be shifted 2 units to the right.

__

3) The vertex form of the equation of a parabola is ...

y = a(x -h)² +k . . . . . . . . for vertex (h, k) and vertical scale factor 'a'

Here, the vertex is (h, k) = (3, 7), and the parabola opens downward. This tells us the sign of 'a' is negative.

The graph is not so clear that it is easy to read the value of 'a' directly from it, but there are several clues.

The zeros of the above function are found at h±√(k/a). This graph shows the zeros to be located such that √(7/a) is slightly less than 2. This means the magnitude of 'a' will be slightly more than 7/2² = 1.75. The y-intercept of the function is 7-9a. It is less than -7, but probably more than -14. This puts bounds on 'a':

-14 < 7-9a < -7

-21/9 < -a < -14/9 ⇒ -2.33 < -a < -1.56

If we assume that 'a' is an integer value, we have bounded its magnitude as being between 1.75 and 2.33, so a=-2 is a reasonable choice.

The equation of the graph may be ...

y = -2(x -3)² +7

8 0

3 years ago