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VARVARA [1.3K]
3 years ago
9

Find the value of x that makes the equation true. 12x=4(x+2)+20

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

7/2

Step-by-step explanation:

12x=4(x+2)+20

12x=4x+8+20

12x-4x=8+20

8x=28

x=28/8

simplify

x=7/2

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Multiply 1/2 by 4/5 to get 4/10 = 2/5.

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And so on, so that the <em>n</em>th term in the sequence is multiplied by <em>n</em>/(<em>n</em> + 1) to get the (<em>n</em> + 1)th term.

Recursively, the sequence is given by

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We can solve this exactly by iterating:

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a_n=\dfrac{(n-1)\cdot(n-2)\cdot(n-3)\cdot\cdots\cdot3\cdot2\cdot1}{n\cdot(n-1)\cdot(n-2)\cdot\cdots\cdot4\cdot3\cdot2}a_1

or

a_n=\dfrac{(n-1)!}{n!}a_1

and with lots of cancellation, we end up with

a_n=\dfrac{a_1}n=\boxed{\dfrac2n}

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Step-by-step explanation:

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Step-by-step explanation:

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