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Varvara68 [4.7K]
3 years ago
11

Consider the standing wave on a guitar string and the sound wave generated by the string as a result of this vibration. What do

these two waves have in common
Physics
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

As the string vibrates, it "moves" the particles in the air, generating what we know as a soundwave.

Because this soundwave is generated by the wave-like motion of the string, makes sense that the soundwave will have some characteristics in common with the standing wave on the guitar string. This means that both waves will have the same normal modes. (So if the principal mode of the vibrating string has a frequency of 440hz, to soundwave also will have that main frequency, and we will hear an A). You can hear almost all the normal modes when you pluck a guitar string, particularly in music, these are called "overtones" or "harmonics"

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What is time taken by the stone ?
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The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

initial velocity(u) = -19.6 m/s

acceleration(a) = 9.81 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds

156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

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For general projectile motion, when the projectile is at the highest point of its trajectory, its acceleration is zero? A)The ho
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Answer:

B) Its velocity is perpendicular to the acceleration.

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