Answer:
freezing point and melting point
Answer:
Explanation:
We shall represent displacement in vector form .Consider east as x axes and north as Y axes west as - ve x axes and south as - ve Y axes . 255 km can be represented by the following vector
D₁ = - 255 cos 49 i + 255 sin49 j
= - 167.29 i + 192.45 j
Let D₂ be the further displacement which lands him 125 km east . So the resultant displacement is
D = 125 i
So
D₁ + D₂ = D
- 167.29 i + 192.45 j + D₂ = 125 i
D₂ = 125 i + 167.29 i - 192.45 j
= 292.29 i - 192.45 j
Angle of D₂ with x axes θ
tan θ = -192.45 / 292.29
= - 0.658
θ = 33.33 south of east
Magnitude of D₂
D₂² = ( 192.45)² + ( 292.29)²
D₂ = 350 km approx
Tan
Answer:
I'm sorry but I dont really know this answer
Choice C.
That's when convection stops.
when wave propagate through the medium the medium particles have two type of possible motions
1) Transverse Waves : here medium particles will move perpendicular to wave propagation and they pull and push perpendicular to the length
2) Longitudinal wave : here medium particles will move to and fro along the length of the medium and the medium particles will push and pull together along the length of the string.
So here in two types of wave motion it will depends on the medium type as well as it will depend on the source how is wave produced.
So the given type of wave in which particles push together and pull apart the wave must be longitudinal wave.
