Period is T = 1/f. The frequency, f, is 5cycles/10s = 0.5. So the period T=1/0.2 = 2.
I would say D) two high tides and two low tides each day
Answer:
Maximum acceleration will be 
Explanation:
We have given mass of the object m = 2 kg
Spring constant k = 55.6 N/m
Amplitude is given as A = 0.045 m
We know that maximum acceleration in SHM is given by
Maximum acceleration 
We know that 
So maximum acceleration =
Answer:
Option D) -0.0707
Explanation:
We are given the following in the question:
Population mean, μ = 45 mp
Sample mean,
= 44.9
Sample size, n = 50
Sample standard deviation, s = 10
Formula:
Putting all the values, we have
Thus, the test statistic is
Option D) -0.0707