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ASHA 777 [7]
3 years ago
7

If Hubble's constant is 73 km/s/Mpc then the age of the universe is 13.4 billion years, assuming a uniform expansion. Suppose it

were discovered that Hubble's constant is actually larger than 73 km/s/Mpc. What effect would this have on the calculated age of the universe?
Physics
1 answer:
ki77a [65]3 years ago
3 0

Answer:

It would decrease the calculated age of the universe

Explanation:

Since the age of the universe is the reciprocal of Hubble's constant, it's therefore if Hubble's constant is increased the age decreases but if the Hubble's constant is decreased, the age of universe increases. Therefore, the age of universe and Hubble's constant are inversely proportional. Conclusively, any attempt to increase Hubble's constant would imply the calculated age of the universe decreases.

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When you drop a ball it accelerates downward at a rate of g. If you instead throw it downward, then its acceleration immediately
Sauron [17]

The acceleration of the ball is always g

Explanation:

An object is said to be in free fall if there is only the force of gravity acting on it. In such situation, therefore, the net force on the ball is

F=mg (1)

where

m is the mass of the ball

g=9.8 m/s^2 is the acceleration of gravity, pointing downward

Applying Newton's second law,

F=ma (2)

where a is the acceleration, and equating (1) and (2), we find the acceleration of an object in free fall:

mg=ma\\a=g

So, any object in free fall has always an acceleration of g (downward), regardless of its initial velocity.

Therefore, in this problem, it doesn't matter what is the direction of the initial velocity of the ball: its acceleration, in fact, will be always equal to g.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

4 0
4 years ago
A car travels first 10 km in 20 minutes and another 10 km in 30 minutes. What is the average speed of the car in m/s?
raketka [301]

Total distance = 10 km + 10 km = 20 km

1 km = 1000 m

20km x 1000 = 20,000 m

Total time = 20 min. + 30 min. = 50 minutes

Average speed = Distance /  time

Average speed = 20,000/50 min

Average speed = 400 m/s

3 0
3 years ago
What is an example of a stable system
oksian1 [2.3K]
Some examples of stable system are:

1) functions of sine

2) DC

3) signum

4) unit step 

5) cosine.

Happy Studying! ^^


6 0
3 years ago
Read 2 more answers
A commuter airplane starts from an airport and takes theroute. The plane first flies to city A, located 175 km away in a directi
bearhunter [10]

Answer:

245.45km in a direction 21.45° west of north from city A

Explanation:

Let's place the origin of a coordinate system at city A.

The final position of the airplane is given by:

rf = ra + rb + rc    where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:

rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km

rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km

The module of this position is:

rf = \sqrt{rfX^2+rfY^2} = 245.45km

And the angle measure from the y-axis is:

\alpha =atan(rfX/rfY) = 21.45\°

So the answer is 245.45km in a direction 21.45° west of north from city A

6 0
4 years ago
A jet engine pushes air at high velocity toward the rear of the plane. Thrust is created moving the plane forward. Which stateme
Lapatulllka [165]
The air pushes the engine with an equal force in the opposite direction.
Whenever force is used there is an opposite yet equal affect.
5 0
3 years ago
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