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malfutka [58]
3 years ago
13

Do you guys know how to solve with equation?

Mathematics
2 answers:
AlexFokin [52]3 years ago
5 0

Answer:

{-8, 3/4}

Step-by-step explanation:

One by one, set the factors equal to zero and solve for v:

8 + v = 0 yields v = -8, and

4v - 3 = 0 yields 4v = 3 and v = 3/4

BigorU [14]3 years ago
3 0
Wouldn’t it be 4v^2+29v-24, like the picture showed.

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3 years ago
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

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Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

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From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

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now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

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Answer:

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Step-by-step explanation:

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