Answer:
For this case we have by definition, that an irrational number is a number that can not be expressed as a fraction \ frac {a} {b}, where a and b are integers and b is different from zero.
A) , it is rational
B), it is rational
C) , it is rational
D) it is not rational.
Step-by-step explanation:
dddddd its dddd
BESTI ILYSM
Answer: Carlos is correct
Step-by-step explanation:
2x^5-250x^2
The first step is to factorize out 2x^2
2x^2(x^3-125)
This can be rewritten as
2x^2(x^3-5^3),
Recall, difference if cube (a^3-b^3)
= (a-b)(a^2 +ab + b^2)
from our equation,
a= x
b = 5.
So the difference of cubes will be
2x^2[(x-5) (x^2 + 5x + 5^2)]
=2x^2[(x-5) (x^2 + 5x + 25)]
Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.
Amber is incorrect because 125 is equal to b3, not b.
Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.
Answer:
D. 13*3^x
Step-by-step explanation:
![3^x +4*3^x^+^1= \\3^x+4*3(3^x)=\\3^x(1+[4*3])=\\3^x(1+12)=\\3^x(13)=\\13*3^x](https://tex.z-dn.net/?f=3%5Ex%20%2B4%2A3%5Ex%5E%2B%5E1%3D%20%5C%5C3%5Ex%2B4%2A3%283%5Ex%29%3D%5C%5C3%5Ex%281%2B%5B4%2A3%5D%29%3D%5C%5C3%5Ex%281%2B12%29%3D%5C%5C3%5Ex%2813%29%3D%5C%5C13%2A3%5Ex)
