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Westkost [7]
3 years ago
6

20 points please helppp me I’m begging u this is due soon please come on ????? Anyone

Physics
2 answers:
Slav-nsk [51]3 years ago
7 0

Answer:

Gases are element .We can change the state of matter by the process of melting,evaporation,sublimation,freezing,condensation.

Virty [35]3 years ago
3 0
Ice can be melted at 0 degrees celsius and become water, water can boil at 100 degrees celsius and become a gas (plz give me brainliest)
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After a large snowstorm, you shovel 2,500 kilograms of snow off of your sidewalk in half an hour. You lift
Delvig [45]
Well, the snow has a total weight G=mg=25,000 N. The work is L=Fd=Gh=1.5*25,000=37,500 J. The power is L/t, where t=1800 seconds. P=37,500/1800=20.833 W.
3 0
3 years ago
When does gravitational lensing occur? High concentrations of dark matter cause length contraction of nearby objects. The gravit
Stella [2.4K]

Answer:

A massive object (like a galaxy cluster) bends the light from an object (like a quasar) that lies behind it.

Explanation:

A massive object, like a galaxy cluster, is able to deform the space-time shape as a consequence of its own gravity, so the light that it is coming from a source that is behind it in the line of sight will be bend or distorts in a way that will be magnified, making small arcs around the cluster with the image of the background object.

This technique is useful for astronomers since they make research of faraway objects (at hight redshift) that otherwise will difficult to detect with a telescope.

4 0
4 years ago
In my trigonometry class, we were assigned a problem on Angular and Linear Velocity.
Rzqust [24]

1) 0.0011 rad/s

2) 7667 m/s

Explanation:

1)

The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

\omega=\frac{\theta}{t}

where

\theta is the angular displacement of the object

t is the time elapsed

\omega is the angular velocity

In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is

\theta=2\pi rad

And the time taken is

t=95 min \cdot 60 =5700 s

Therefore, the angular velocity of the telescope is

\omega=\frac{2\pi}{5700}=0.0011 rad/s

2)

For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

v=\omega r

where

v is the linear velocity

\omega is the angular velocity

r is the radius of the circular orbit

In this problem:

\omega=0.0011 rad/s is the angular velocity of the Hubble telescope

The telescope is at an altitude of

h = 600 km

over the Earth's surface, which has a radius of

R = 6370 km

So the actual radius of the Hubble's orbit is

r=R+h=6370+600=6970 km = 6.97\cdot 10^6 m

Therefore, the linear velocity of the telescope is:

v=\omega r=(0.0011)(6.97\cdot 10^6)=7667 m/s

4 0
3 years ago
A flap of tissue that prevents blood from flowing back is a(n)________ .
ioda
A valve is a flap of tissue that prevents blood from flowing back
6 0
3 years ago
12- Calculate the power when a force of 60N moves an object over a distance of 0.6 km in 20
alexandr1967 [171]

Hi there!

To solve, we must begin by calculating the total WORK done on the object.

W = F · d (Force · displacement)

Plug in the given values. Remember to convert km to m:

1 km = 1000 m

0.6 km = 600 m

W = 60 · 600 = 36000 J

Now, we can solve for power:

P = W/t

Convert minutes to seconds:

1 min = 60 sec

20 min = 1200 sec

P = 36000/1200 = 30 W ⇒ Choice D.

3 0
3 years ago
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