At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.
<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
- At the highest point, the ball doesn't go more high. So its vertical velocity is zero.
- However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
- u= initial velocity, θ= angle of projection
<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
- During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction.
- But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.
Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
A- neither the ball's velocity nor its acceleration are zero.
B- the ball's acceleration points upward.
C- the ball's acceleration is zero but its velocity is not zero.
D- the ball's velocity points downward.
Learn more about the projectile motion here:
brainly.com/question/24216590
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Formula for kinetic energy is 1/2mv^2 so that answer should most probably be 94521.6J
The most i can help with is Saliva glands or salivary glands
You could say almost anything.
For example:
phones,
cars,
computers,
clocks,
hydraulics,
bicycles,
the hadron collider,
Planes,
and so on.
Answer:
a
The speed of wave is 
b
The new speed of the two waves is 
Explanation:
From the question we are told that
The mass of the string is 
The length is 
The tension is 
Now the velocity of the first wave is mathematically represented as

Where
is the linear density which is mathematically represented as

substituting values


So


Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )