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Paladinen [302]
4 years ago
10

Calculate the resistance of an electric bulb which allows a 10 A current when connected to a 220 V power source

Physics
1 answer:
kodGreya [7K]4 years ago
4 0

Resistance can be calculated by Ohm's law

As per ohm's law we will have

V = i * R

here we will have

voltage = 220 volts

current = 10 A

So by the above formula we will have

220 = 10* R

R = 22 ohm

So resistance of the bulb is 22 ohm.

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In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w
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Answer:

v_2=-133.17m/s, the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before (p_i) and after (p_f) the explosion. We will take the east direction as positive.

Before the explosion we have p_i=m_iv_i=Mv_i.

After the explosion we have pieces 1 and 2, so p_f=m_1v_1+m_2v_2.

These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.

Since we know momentum must be conserved we have:

Mv_i=m_1v_1+m_2v_2

Which means (since we want v_2 and M=m_1+m_2):

v_2=\frac{Mv_i-m_1v_1}{m_2}=\frac{Mv_i-m_1v_1}{M-m_1}

So for our values we have:

v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s

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3 years ago
A 12.0 g sample of gas occupies 19.2 L at STP. what is the of moles and molecular weight of this gas?​
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At STP, 1 mole of an ideal gas occupies a volume of about 22.4 L. So if <em>n</em> is the number of moles of this gas, then

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(12.0 g) / <em>n</em> ≈ 14.0 g/mol

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