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sveta [45]
3 years ago
10

No links please, links never work, this is science not physics

Physics
1 answer:
stiks02 [169]3 years ago
7 0

Answer:

b and c are the answers

A is an opinion, D is a superstitious belief because they haven’t found Jesus obviously

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How do you use the SI conversion tool to perfom metric conversions?
Leno4ka [110]
Is there supposed to an attachent like a pic or somthing?
4 0
3 years ago
Question 2
Ksivusya [100]

5.77 ×10^1^4 Hz is the green photon's frequency .

The distance between similar points (adjacent crests) in adjacent cycles of a waveform signal that is propagated in space is known as the wavelength. A wave's wavelength is often measured in meters (m), centimeters (cm), or millimeters (mm) (mm). The relationship between frequency and wavelength is inverse.

<h3>Given:</h3>

Wavelength of green light = 520 nm

f = c / λ

where, f = Frequency

            c = Speed of light = 3 × 10^8 m/s

            λ = Wavelength of light

∴ f = c / λ

  f = \frac{3*10^8}{520 * 10^-^9}

    = 5.77 ×10^1^4 Hz

Therefore,  5.77 ×10^1^4 Hz is the green photon's frequency .

Learn more about wavelength here:

brainly.com/question/10728818

#SPJ1

4 0
2 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
Read 2 more answers
What is the kinetic energy of a 150 gram object moving at a velocity of 100 m/s?
Alex Ar [27]

Answer:

750 J

Explanation:

lets convert mass into kg first , 150 /1000 = 0.15 kg

kinetic energy =  \frac{mv^{2} }{2} =  \frac{0.15*100^{2} }{2}  = 750 J

3 0
3 years ago
An inventor develops a stationary cycling device by which an individual, while pedaling, can convert all of the energy expended
mr Goodwill [35]

Answer:

Q=94185\ J

Explanation:

Given:

  • mass of water, m=0.3\ kg
  • initial temperature of water, T_i=20^{\circ}C
  • final temperature of water, T_f=95^{\circ}C
  • specific heat of water, c=4186\ J.kg^{-1}.K^{-1}

<u>Now the amount of heat energy required:</u>

Q=m.c.\Delta T

Q=0.3\times 4186\times (95-20)

Q=94185\ J

Since all of the mechanical energy is being converted into heat, therefore the same amount of mechanical energy is required.

4 0
3 years ago
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