Answer:
Prove: ΔPYJ ≅ ΔPXK
Step-by-step explanation:
Overlapping triangles are said to be triangles that share at least part of a side or an angle.
To prove ΔPYJ is congruent to ΔPXK
First we would draw the diagram obtained from the given information.
Find attached the diagram.
Given:
JP = KP
PX = PY
From the diagram, ΔPYJ and ΔPXK share the line KJ (part of the side of each of the triangle)
KJ ≅ KJ (A reflexive property - the segment is congruent to itself)
In ∆PYJ
JP = KP + KJ
In ∆PXK
KP = JP + KJ
Since JP = KP
KP + KJ = JP + KJ
PJ ≅ PK
The overlapping section makes a smaller triangle KXJ
∠K = ∠J (opposite angles of congruent sides are equal)
In ∆PYJ: PY + YJ + PJ (sum of angles in a triangle)
In ∆PXK: PX + XK + PK (sum of angles in a triangle)
If ΔPYJ ≅ ΔPXK
PY + YJ + PJ = PX + XK + PK
XK ≅ YJ
Therefore, ΔPYJ ≅ ΔPXK
E) sqrt(30)
This is a nice problem. It was helpful to read the topic at the top.
Notice that the two right triangles are similar. Their sides are in proportion.
That is the side '3' is what 'x' is in the other triangle (you need to rotate it!)
Then 'x' is similar to '10'
3/x=x/10 ---> x^2=30, x=sqrt(30)
If you are patient, you can check that for sqrt(30) pythagoras theorem works for all the triangles.
Best
Then
See the photo attached below, answer is D
Answer:
56 and 7 its going by 5
Step-by-step explanation:
Answer:
The answer is 18
hope this helps
have a good day :)
Step-by-step explanation:
