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Sphinxa [80]
2 years ago
6

Given: t is tangent at B

Mathematics
2 answers:
oksian1 [2.3K]2 years ago
8 0

Answer:

70

Step-by-step explanation:

Given

∠PDB = 110°

PDis the tangent to the circle whose centre is E

Construction

Join points D and E.

∠DPE= 90° [Since angle in a semi circle is 90°]

Also ∠PDE = 90° [Since radius ⊥ tangent]

From the figure we have,

∠PDB=∠PDE + ∠DBE

i.e. 110° = 90° + ∠DBE

Therefore, ∠DBE =20°

Now in ΔBED, BE = ED [Radii]

So, ∠EDB = ∠EBD =20°

In ΔBPD, we have

∠DPE = 90° & ∠DBE = 20°

Therefore, ∠DPB = 70°

Bezzdna [24]2 years ago
6 0

Answer:

70 is the correct answer

Step-by-step explanation:

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