All categories

3 years ago

How do you know if a graph is exponential???

Mathematics

2 answers:

AlexFokin [52]3 years ago

8 0

When is standing up right with a line

Elena-2011 [213]3 years ago

4 0

Answer:

The graph passes through the point (0,1)

The domain is all real numbers.

The range is y>0.

The graph is increasing.

The graph is asymptotic to the x-axis as x approaches negative infinity.

The graph increases without bound as x approaches positive infinity.

The graph is continuous.

can u give me the brainliest ?

You might be interested in

The ratio of cows to pigs on the farm is

zheka24 [161]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

(a) The books in any order

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

(b) The mathematics book, not together

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

(c) The novels must be together and the chemistry books, together

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

(d) The mathematics must be together and the chemistry books, not together

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

If triangle he an area of 36 and a height of 12 calculate the length of the base.

vovangra [49]

Answer:

Below.

Step-by-step explanation:

A = 1/2bh for a triangle.

36 = 1/2b(12)

36 = 6b

---- ----

6 6

b = 6

3 0

2 years ago

A school counselor considered several different ways to report on the 7th grade class:

almond37 [142]

Answer:

for every 5 girls there are 4 boys

4 0

3 years ago

When they movies into their new home the Marino's put new light bulbs in all the fixtures the new house had 6 rooms and each roo

Harrizon [31]

Answer: the number of new light bulbs that they put in is 36

Step-by-step explanation:

The Marino's put new light bulbs in all the fixtures the new house.

Each fixture used 2 light bulbs and each room had 3 fixtures. This means that the number of bulbs in each room would be 3×2 = 6 bulbs.

The new house had 6 rooms. This means that the total number of bulbs in 6 rooms would be

6 × 6 = 36 bulbs

8 0

4 years ago