Answer:x^2+2x+3
Step-by-step explanation:
I’m assuming you meant 2x^4+4x^3+6x^2...
So you can pull out 2x^2 from all of the polynomials...
And this equation isn’t able to be simplified anymore. Hope this helps!
Y=5x+3. because your y axis is moved
Answer:
x=3, y= -6
Step-by-step explanation:
make 4+y= -x as equation (1) and make y=2x-10 as equation (2, then you must find a third equation either from equation (1)or (2). If you choose to find equation (3) from (2) it will be y=2x-10 , then substitute equation (3) from (1) because you can't choose (2) , then it will be 4+(2x-10)= -x
the answer will be x =2
substitute x from equation (3)
y=2x-10
y=2 (2)-10
y= -6
Answer:
The volume of the figure is 20,925.0mm^3.
Step-by-step explanation:
Firstly we know that the Diameter = 14mm and Height = 136mm.
Area of Circle = 3.14xR^2 Radius = Diameter / 2
Area of Circle = 3.14x7mm^2 = 153.86mm
Volume = 153.86 x 136 = 20,924.96
Then round, to get 20,925.0
Let me know if this is helpful
Answer:
D) ![\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%5Cfrac%7B5%7D%7B4%7D%5C%5C-%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For matrix ![\left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
the inverse matrix is the transpose of the cofactor matrix, divided by the determinant: ![\dfrac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bad-bc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dd%26-b%5C%5C-c%26a%5Cend%7Barray%7D%5Cright%5D)
Your inverse matrix is: ![\dfrac{1}{2(-3)-(1)(2)}\left[\begin{array}{cc}-3&-1\\-2&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%28-3%29-%281%29%282%29%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-3%26-1%5C%5C-2%262%5Cend%7Barray%7D%5Cright%5D)
so the solution is ...
![\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{cc}\frac{3}{8}&\frac{1}{8}\\\frac{1}{4}&-\frac{1}{4}\end{array}\right] \cdot\left[\begin{array}{c}2\\4\end{array}\right] =\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right] \qquad\text{matches selection D}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B8%7D%26%5Cfrac%7B1%7D%7B8%7D%5C%5C%5Cfrac%7B1%7D%7B4%7D%26-%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2%5C%5C4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%5Cfrac%7B5%7D%7B4%7D%5C%5C-%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%5Ctext%7Bmatches%20selection%20D%7D)
