F(3) = 16, you simply plug in 3 for x to find the answer.
Answer:
minimum of 13 chairs must be sold to reach a target of $6500
and a max of 20 chairs can be solved.
Step-by-step explanation:
Given that:
Price of chair = $150
Price of table = $400
Let the number of chairs be denoted by c and tables by t,
According to given condition:
t + c = 30 ----------- eq1
t(150) + c(400) = 6500 ------ eq2
Given that:
10 tables were sold so:
t = 10
Putting in eq1
c = 20 (max)
As the minimum target is $6500 so from eq2
10(150) + 400c = 6500
400c = 6500 - 1500
400c = 5000
c = 5000/400
c = 12.5
by rounding off
c = 13
So a minimum of 13 chairs must be sold to reach a target of $6500
i hope it will help you!
A break even problem is found when you calculate starting a buisieness
so lets ssay you have to buy 3 coppy machines and each machine costs 2000 dollars,
the people who want to use your coppy machines have to pay $0.40 per page
so you have spent 6000 dollars already
when you break even, it is when your earnings equals your expenditure (how much you earned equals how much you paid)
