Here's how to figure out this problem: add up all the numbers in the mark category and divide by the # of numbers there are.
So....
6 + 7 + 8 + 9 + 10 ÷ 5 = 8
8 is your final answer.
Your sequence appears to be geometric with a common ratio of 2. It can be described by
a(n) = (-2 2/3)·2^(n-1)
_____
This can be written in a number of other forms, including
a(n) = (-8/3)·2^(n-1)
a(n) = (-1/3)·2^(n+2)
a(n) = (-4/3)·2^n
X = 6 after distributing then adding 39 to both sides and then divide by 13
Answer:
5 ≥ 9*.15 + x*.25
He can buy up to 14 candies
Step-by-step explanation:
Total money ≥number of peppermints * cost per peppermint + number of sour candies * cost per sour candy
We know he has 5 dollars. He bought 5 peppermints at $.15 cents each and x sour candies at $.25 each
Substituting in
5 ≥ 9*.15 + x*.25
5≥1.35 + .25x
Subtract 1.35 on each side
5-1.35 ≥ 1.35-1.35+.25x
3.65≥.25x
Divide by .25 on each side
3.65/.25 ≥ .25x/.25
14.6 ≥ x
He can buy up to 14 candies. You can't buy part of a candy